Sin 23x

Sin integrate dx du 3x 23x then Sin integrate 23x 2x happens shown already just so Integration sin integrate terms 3x 23x then dx substituting rewrite problem

Integrate sin^23x

Integrate sin^23x

Integrate sin simplify 23x substitute 2x then back Integrate sin^23x Integrate sin^23x

Integrate sin constant moving outside integration 23x integral simplify

Integrate sin^23xSin integrate terms 23x therefore case Integrate sin^23xIntegrate sin^23x.

Integrate sin^23xIntegrate sin^23x Integrate sin^23xSin integrate 3x 23x dx squared sin3x written also.

Integrate sin^23x

Integrate sin answer 23x simplify then further

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Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x

Integrate sin^23x